Algorithms on Strings, Trees and Sequences: Computer Science by Dan Gusfield PDF

By Dan Gusfield

ISBN-10: 0521585198

ISBN-13: 9780521585194

ISBN-10: 1352542552

ISBN-13: 9781352542554

Routinely a space of analysis in machine technological know-how, string algorithms have, in recent times, develop into an more and more very important a part of biology, rather genetics. This quantity is a accomplished examine desktop algorithms for string processing. as well as natural laptop technology, Gusfield provides huge discussions on organic difficulties which are solid as string difficulties and on equipment built to unravel them. this article emphasizes the elemental rules and strategies primary to present day functions. New techniques to this advanced fabric simplify tools that in the past were for the professional by myself. With over four hundred routines to enhance the fabric and strengthen extra themes, the booklet is appropriate as a textual content for graduate or complex undergraduate scholars in machine technological know-how, computational biology, or bio-informatics

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Additional info for Algorithms on Strings, Trees and Sequences: Computer Science and Computational Biology

Example text

This means that there is an endless chain of elements of b, each being an element of the previous one. The simplest example is the “circular” set defined by the equation J = {J} (if it exists). Here the chain is J J J . . The property of foundedness ensures that a set does not contain a bottomless pit. 1 Ordinal Numbers 47 Fig. 3. Foundedness: If b ⊂ a is non-empty, and a is founded, then there is x ∈ b such that x ∩ b = ∅; here we have x = {r , s}, b = {x, u, v, w} with r ≠ u, v, w and s ≠ u, v, w.

8, the set A of stars, the set B of crosses and the set C of plusses are equipollent. The functions f : A → B and g : B → C are both bijections. The composition of g and f is a bijection h = g ◦ f : A → C. The purpose of this example is to show that equipollence is a feature independent of the shape, or “structure” of the set. It only tells us that each element from the first set can be matched with an element from the second set, and vice-versa. Proposition 18 For all sets a, b and c, we have: (i) (Reflexivity) a is equipollent to a.

This defines a retraction of f . (vi) Let f be epi. For every x ∈ b, let F (x) = {y | y ∈ a, f (y) = x}. Since f is epi, no F (x) is empty, and F (x) ∩ F (x ) = ∅ if x ≠ x . By the axiom of choice 8, there is a set q ⊂ a such that q ∩ F (x) = {qx } is a set with exactly one element qx for every x ∈ b. Define s(x) = qx . This defines the section s : b → a of f . (vii) The case a = ∅ is trivial, so let us suppose a ≠ ∅. Then the characterizations (v) and (vi), together with the fact that “mono + epi = iso”, answer our problem.

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Algorithms on Strings, Trees and Sequences: Computer Science and Computational Biology by Dan Gusfield


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